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A cubical container of side length $‘ L ’$ is half filled with liquid of density $ρ$ and placed on the floor of an elevator accelerating downward with acceleration $' g / 2' .$ Now the container is given a horizontal acceleration parallel to one of the horizontal edge then ( $P_{0} =$ atmospheric pressure)

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Pressure at center of container will remains unchanged upto a certain value of horizontal acceleration

The maximum gauge pressure at the bottom surface when liquid is about to over flow is $P_{0} + \frac{ρ g L}{2}$

The horizontal acceleration for which liquid over flow takes place is $\frac{g}{2}$

The minimum pressure at the bottom surface when liquid is about to over flow is $P_{0}$

answer is A, B, D.

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Detailed Solution

Upto horizontal acceleration $g / 2$ there will be no over flow.
$\tan 45^{ο} = \frac{a_{h}}{g_{e f f}} = 1 ∴ a_{h} = g / 2$

Height of liquid at the centre is unchanged

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