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Q.

A current carrying conductor AB is bent in a form of a semi circle of radius r and it is placed in a uniform magnetic field of induction B as shown in figure. Then force experienced by the conductor is

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a

irB

b

2πirB

c

Zero

d

2irB

answer is A.

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Detailed Solution

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F→=ile→×B→. Here equivalent length le is parallel to B→.

Hence F=ileBsinθo=0

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A current carrying conductor AB is bent in a form of a semi circle of radius r and it is placed in a uniform magnetic field of induction B as shown in figure. Then force experienced by the conductor is