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A current carrying conductor is in the form of a sine curve as shown, which carries current I. If the equation of this curve is $Y = 2 \sin (\frac{π x}{L})$ and a uniform magnetic field B exists in space.

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Force on wire is BIL if field is along Z axis.

Force on wire is 2BIL if field is along Y axis

Force on wire is zero if field is along X axis

Force on wire is BIL if field is in the XY plane making an angle 30° with X-axis.

answer is B, C, D.

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Detailed Solution

Let O and P be the end points of wire. Hence force on current (I) carrying wire placed in uniform magnetic field is $\vec{F} = Ι (\vec{O P} \times \vec{B})$

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