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Q.

A current carrying loop is placed in a uniform magnetic field pointing in negative z direction. Branch PQRS is a three quarter circle, while branch PS is straight. If force on branch PS is F, force on branch PQR is

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a

2πF

b

F2

c

2F

d

πF2

answer is A.

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Detailed Solution

Forces of the different parts of the loop are shown in figure. The force on part RS is also F. The net force on the close loop is zero and so

                                        F'=F2+F2    = 2F

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