A current carrying ring of radius r, carrying a current i, is placed in the uniform magnetic field of induction $\overrightarrow{\mathrm{B}}$ directed into the plane of the ring, as shown in the figure. Then

Each small element of the ring experiences a radially outward force $(∆\overrightarrow{F}=i\overrightarrow{∆l} x \overrightarrow{B})$. As a result a tensile force is induced in the wire. Net force $\left(\sum _{ }∆\overrightarrow{\mathrm{F}}\right)$ on the ring is zero. Angle between magnetic dipole moment $\overrightarrow{\mathrm{M}}$ and magnetic field $\overrightarrow{\mathrm{B}}$ is zero. Hence net torque $(\mathrm{\tau }=\mathrm{MBsin}{0}^{\mathrm{o}})$ is zero.