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A current carrying straight conductor is placed in a uniform magnetic field and force experienced by the conductor is 6N. When the conductor is rotated through an angle of 90° in the plane containing the rod and the field, force experienced by the rod is 8 N. Then maximum possible force experienced by the conductor when placed in the same magnetic field is

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14 N

16 N

12 N

10 N

answer is C.

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Detailed Solution

$\begin{array}{l} F_{1} = ilBsinθ and F_{2} = ilBsin (90^{0} \pm θ) = ilBcosθ \\ ∴ F_{\max} = ilB = \sqrt{F_{1}^{2} + F_{2}^{2}} = \sqrt{6^{2} + 8^{2}} N = 10 N \end{array}$

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