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Q.

A current carrying wire kept in a uniform magnetic field, will experience a maximum force when it is

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a

at an angle of 60° to the magnetic field

b

parallel to the magnetic field

c

at an angle of 45° to the magnetic field

d

perpendicular to the magnetic field

answer is A.

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Detailed Solution

Magnitude of force on a current carrying conductor kept in internal magnetic field,
F= B.I.l sinθ
where Bmagnetic field, I  current, l length of conductor
Force would be maximum when sin θ is maximum. So, sin θ must be equal to 1, Thus, θ=π2
Hence, current carrying wire is kept perpendicular to the magnetic field to experience maximum magnetic force.

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