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A current $I = 10 \sin (100 π t)$ amp. is passed in first coil, which induces a maximum e.m.f of $5π$ volt in second coil. The mutual inductance between the coils is -

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15 mH

10 mH

5 mH

25 mH

answer is D.

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Detailed Solution

$I = 10 \sin 100 π t, \frac{d I}{d t} = 10^{3} π \cos 100 π t$

$ε = M \frac{d I}{d t} f o r ε_{\max}, \frac{d I}{d t} should be maximum$

$5 π = M 10^{3} π, M = 5 m H$

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