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Q.

A current I1 carrying wire AB is placed near another long wire CD carrying current I2. If wire AB is free to move, it will have

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a

neither rotational nor translational motion

b

translational motion only

c

rotational as well as translational motion

d

rotational motion only

answer is C.

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Detailed Solution

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Magnetic force due to the wire CD will be inside the plane on the wire AB. So, the force on wire AB will be in upwards direction and it will be maximum at end A and minimum at end B (as the magnetic field strength decreases away from the wire CD).

Hence, the wire AB will have both translational as well as rotational motion.

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A current I1 carrying wire AB is placed near another long wire CD carrying current I2. If wire AB is free to move, it will have