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A current is passed through 500 mL of an aqueous solution of $C a l_{2} .$ After sometime, it is observed that 50 millimoles of $l_{2}$ have been formed. Which of the following statements is(are) correct?

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The number of faradays of charge passed through the solution is 0.10F.

The volume of dry $H_{2}$ at STP that has been formed during electrolysis is 1120 mL

The pH of the solution is nearly 0.7

The mass of calcium produced is 2.0 g

answer is A, B.

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Detailed Solution

$(1) [\begin{array}{l} M m o l e s I_{2} = 50 \Rightarrow 100 m F P a s s e d = 0.1 F \\ (2 l^{Θ} \to I_{2} + 2 e^{-}) \end{array}]$

$(2)$ Also number of $H_{2} = \frac{1}{2} \times$ number of mF

$= \frac{1}{2} \times 100 = 50 \Rightarrow V_{H_{2}} a t S T P$ .

$= 50 \times 22.4 m l = 1120 m L$

$(3)$ 100 moles of $\overset{Θ}{O} H$ left

$\Rightarrow [\overset{Θ}{O} H] = \frac{100}{500} = 0.2$

$\Rightarrow p O H = - \log 0.2 = 0.7$

$\Rightarrow p H = 13.3$

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