Q.

A current of 16A is made to pass through a conductor in which the number density of free electrons is 4×1028 m3 and is area of cross section is 105m2. The average velocity of free electrons in the conductor is

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a

1.6×104ms1

b

3.2×104ms1

c

6.4×104ms1

d

2.5×104ms1

answer is B.

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Detailed Solution

vd=ineA

=164×1028×1.6×1019×105

=164×1.6×104

=164×16×103

=14×103

=2.5×10-4 m/s

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