A current of 2 A is passed for 5 h through a molten tin salt to deposit 22.2 g tin. What is the oxidation state of tin in salt ? [At. Wt of Sn =118.69g ] ______

Equivalents of tin $\mathrm{=}\frac{ \mathrm{i}.\mathrm{t} }{96500}$
Or $\frac{22.2}{ \mathrm{eq}.\mathrm{wt} }=\frac{2\times 5\times 60\times 60}{96500}$
Eq. Wt = 59.5
$\therefore$ Valency of tin
$\mathrm{=}\frac{ \mathrm{at}.\mathrm{wt} }{ \mathrm{eq}.\mathrm{wt} }=\frac{118.69}{59.5}\approx 2( \mathrm{an} \mathrm{integer})$
Therefore, Sn²⁺ + 2e^- →Sn
Thus, oxidation state of tin (Sn) in salt is +2.