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A current of $2 A$ passes through a circuit for $1$ minute. If the potential difference between the terminals of the circuit is $3 V,$ What is the work done in transferring the charge?

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430 J

360 J

240 J

386 J

answer is B.

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Detailed Solution

The work done in transferring the charge is

360 J

.
Here, given that current

I = 2 A

Time

t = 1 \min

\Rightarrow

t = 60 s

and
Potential difference

V = 3 Volts

We can first measure the amount of electric charge(

Q

) that is going through the circuit. It can be computed as follows:
We know that

Q = I \times t

So,

Q = 2 A \times 60 s

\Rightarrow Q = 120 C

And electric potential

V = \frac{w}{Q}

Where

V

is the potential difference,

W

is the work done and

Q

is the charge.

\Rightarrow

W = V \times Q

\Rightarrow

W = 3 V \times 120 C

\Rightarrow

W

= 360 J

Hence, the work done in transferring the charge is

360 J

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