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Q.

A current of 2.0 A when passed for 5 hrs through a molten salt, deposits 22.2 g of metal ( of atomic weight 177 ). The oxidation state of metal in metal salt is (round off the answer to nearest integer)

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a

answer is C.

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Detailed Solution

According to Faraday's Law:

W=E×I×t96500=Atomic weightn-factor×I×t96500

Substitute the values:

n-factor=Atomic weight×I×tW×96500=177×2×5×60×6022.2×96500≅3

Hence, the oxidation state of metal= +3

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