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Q.

A current of 3.7 ampere is passed for 6 hr between Ni electrodes in 0.5 litre of 2 M solution of Ni(NO₃)₂ . What will be the molarity of solution at the end of electrolysis?

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a

cannot be predicted

b

<2M

c

>2M

d

2M

answer is B.

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Detailed Solution

$Time = 6 hr = 6 x 60 x 60 = 21600$

$m = \frac{E x 3.7}{96500} x 21600 = \frac{59}{2 (96500)} 21600 x 3.7$

$M = 6.6 x 3.7 = 24.42$

$M = \frac{Wt}{GMW} x \frac{1}{0.5}$

$M = \frac{24.42}{5.9} x \frac{1}{0.5} = 0.89$

$0.89 M < 2 M$

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