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A current of three A is flowing in a liner conductor having a length of forty cm. The conductor is placed in a magnetic field of strength 500 Gauss and makes an angle of 30⁰ with the direction of the filed. It experiences a force of magnitude

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3 × 10² N

3 × 10^-2 N

3 × 10⁴ N

3 × 10^-4 N

answer is C.

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Detailed Solution

$\begin{array}{l} F = Bilsin θ \\ F = 500 \times 10^{- 4} \times 3 \times 40 \times 10^{- 2} \times \frac{1}{2} = 3 \times 10^{- 2} N \end{array}$

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