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Q.

A current of 4.8 A is flowing in a conductor the number of electrons passing per sec through

            the conductor will be

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a

3×1019

b

7.68×1020

c

7.68×1019

d

3×1020

answer is A.

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Detailed Solution

i=4.8 A Find out n/t i=net nt=i/e=4.81.8×10-19=3×1019

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A current of 4.8 A is flowing in a conductor the number of electrons passing per sec through            the conductor will be