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Q.

A current of 9.95 amp following for 10 minutes,deposits 3 gm of a metal. Equivalent weight of the metal is

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a

12.5

b

18.5

c

21.5

d

48.5

answer is D.

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Detailed Solution

$\frac{w}{E} = \frac{it}{96500} \frac{3}{E} = \frac{9.95 \times 10 \times 60}{96500} E = 48.5$

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