A current of dry air was bubbled through a bulb containing 30 g of an organic compound in 200 g of water, then through a bulb at the same temperature, containing water and finally through a tube containing anhydrous CaCl₂, the loss in mass of bulb containing water was 0.03 g and gain in mass of CaCl₂ tube was 2g, then molecular mass of organic compound is
$(\mathrm{Hint}: \frac{{\mathrm{P}}^0-\mathrm{P}}{{\mathrm{P}}^0}=\frac{ \mathrm{Loss} \mathrm{in} \mathrm{mass} \mathrm{of} \mathrm{solvent} \mathrm{bulb} }{ \mathrm{Gain} \mathrm{in} \mathrm{mass} \mathrm{of} {\mathrm{CaCl}}_2 \mathrm{tube} } )$