A current strength of 9.65 amperes is passed through excess fused AlCl₃ for 5 hours. How many litres of chlorine will be liberated at STP? (F=96500 C)

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2.016

1.008

11.2

20.16

answer is D.

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Detailed Solution

$1 F ⟶ 11.2 {LCl}_{2} at STP (2 {Cl}^{-} ⟶ {Cl}_{2} + 2 e^{-})$
$\begin{array}{l} ∴ No . of Faradays = \frac{9 .65 \times 5 \times 60 \times 60}{96500} = 1 .8 \\ ∴ Vol . of {Cl}_{2} = 1 .8 \times 11 .2 L = 20 .16 \end{array}$

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