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A cycloalkane was subjected to reaction with silver nitrate solution to form a pale yellow color ppt as shown below. The compound is

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answer is D.

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Detailed Solution

Reaction of silver nitrate with chlorides forms white ppt., Bromide give pale yellow ppt, iodide gives yellow ppt. Hence the answer is 4.

Moreover option-2 has bromine group but it is connected to sp2 carbon, it cant be removed easily and form ppt.

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