A cylinder, a cone, and a hemisphere all have the same base and height. Their volume proportion is

Given solid is combination of cylindrical , cone and hemisphere Because the volume of a hemisphere is half that of a sphere, it is written as Volume of hemisphere $\frac{2}{3}\pi R^3$, where r is the radius of the hemisphere.

Volume of the cone is $\frac{1}{3}\pi R^{2}h$

Volume of the cylinder is $=\frac{1}{3}\pi r^2{h}_1+\pi r^2{h}_1+\frac{2}{3}\pi r^3$

Let the common base radius be $=r$

Then the height of the cylinder and the cone $=r$

Volume of the cylinder $=\pi {\mathrm{r}}^2 \mathrm{h}=\pi {\mathrm{r}}^2\times \mathrm{r}=\pi {\mathrm{r}}^3$

Volume of the cone $=\frac{1}{3}\pi r^{2}h=\frac{1}{3}\pi r^2\times r=\frac{1}{3}\pi r^3$

Volume of hemisphere$=\frac{2}{3}\pi r^3$

 required ratio $=\pi r^3:\frac{1}{3}\pi r^3:\frac{2}{3}\pi r^3$

$=1:\frac{1}{3}:\frac{2}{3}$

$=3: 1: 2$