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A cylinder of mass 12 kg is sliding on plane with an initial velocity $20 m s^{- 1}$ . If the coefficient of friction between the surface and the cylinder is 0.5, before stopping, the cylinder describes a distance of... $(g = 10 {ms}^{- 2})$

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5 m

10 m

20 m

40 m

answer is A.

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Detailed Solution

$S = \frac{u^{2}}{2 μg} = \frac{120^{2}}{2 \times 0.5 \times 10} = 40 m$

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