A cylindrical container has a diameter of base 56 cm and contains sufficient water to submerge a rectangular solid of iron whose dimensions are $32 c m × 22 c m × 14 c m$ . What will be the rise in the level of the water after the solid has completely submerged?

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5cm

2cm

4cm

3cm

answer is C.

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Detailed Solution

Given as follows,
Diameter of base of the cylindrical container = 56 cm
The volume of the cylinder =

π r 2 h

The volume of water rising in a cylindrical container is equal to the volume of the rectangular solid.
We equate the volume of water rise in a cylindrical container and the volume of the rectangular solid,

227 × 28 × 28 × h = 9856

h = 9856 × 7 22 × 784

h = 4cm
Thus, the rise in the level of the water after the solid has completely submerged will be 4 cm.
Therefore, the correct option is 3.

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