Q.

A cylindrical rod of length 64 cm and cross-section radius r=(2/π)cm is placed at a distance 50 r from a infrared point source S of power 1.25 kW as shown in the figure. The lateral surface of the rod is perfectly insulated from the surroundings. The cross-section A absorbs 80% of the incident energy, has temperature TA in steady state. The surface B is radiating energy into space and the wavelength emitted by it with maximum energy density is 100,000A. Find the value of TA (temperature of end A in Kelvin) if conductivity varies with temp as K=TTA. Assume that the rate of flow of heat through the rod is steady.(Wein’s constant = 0.003mK)

Question Image

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

answer is 500.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Intensity of the source at the cross-section 
l=P4π(50r)2=1.25×1034π(50r)2
Power absorbed by the end A
TB=0.003100000×1010=300K
 

Question Image

0L0.1TA.dx4×104=TATBTdTTA=500K

Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon