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Q.

A cylindrical rod of length 64cm and cross-section radius  r=(2/π) cm is placed at a distance 50r from a infrared point source S of power 1.25 kW as shown in the figure. The lateral surface of the rod is perfectly insulated from the surroundings. The cross section A absorbs 80% of the incident energy, has temperature TA  in steady state. The surface B is radiating energy into space and the wavelength emitted by it  with maximum energy density is 100,000 A0  . The value of  TA is  X×100 ( TA is temperature of end A in Kelvin) if conductivity varies with temp as  K=TTA. Assume that the rate of flow of heat through the rod is steady (Wein’s constant=0.003 Km). Find the value of X
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Detailed Solution

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Intensity of the source at the cross-section A
l=P4π(50r)2=1.25×1034π(50r)2
Power absorbed by the end A
TB=0.003100000×1010=300K

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0j0.1TA.dx4×104=TATBTdT TA=500K

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