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A cylindrical rod with one end in a steam chamber and the other end is in ice. It is found that 1gm of ice melts per second. If the rod is replaced by another one of same material double the length and double area of cross section, The mass of ice that melts per second is

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2 gm

4 gm

0.5 gm

1 gm

answer is C.

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Detailed Solution

$Q = mL = \frac{KA (θ_{1} - θ_{2}) t}{ℓ} \Rightarrow \frac{m_{2}}{m_{1}} = \frac{A_{2}}{A_{1}} \times \frac{l_{1}}{l_{2}} = 1$

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