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A cylindrical tank has a hole of area $2 {cm}^{2}$ at its bottom. If water is poured into the tank from a tube above it at the rate of 100 cm³s^-1, then the maximum height upto which water can rise in the tank is (Acceleration due to gravity g=10 ms^-2)

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2.5 cm

1.25 cm

5.5 cm

answer is B.

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Detailed Solution

when input water is equal to output the height of the liquid column will be maximum.

$100 \times 10^{- 6} = \sqrt{2 g h} A$

$10^{- 4} = \sqrt{2 \times 10 \times h} \times 2 \times 10^{- 4}$

solving h=1.25 cm

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