A cylindrical tank is placed on a platform 5 m high. Initially the tank is filled with water up to a height 5 m. An orifice is made in the side wall of tank just at the bottom. Speed with which water coming out of the orifice hits ground is nearly: (take g = 10 m/s²)

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7.2 m/s

14 m/s

9 m/s

18 m/s

answer is C.

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Detailed Solution

$u_{x} = \sqrt{2 gh} = \sqrt{2 \times 10 \times 5} = 10 m / s^{- 1} u_{y} = \sqrt{2 gH} = \sqrt{2 \times 10 \times 5} = 10 {ms}^{- 1} Speed = \sqrt{u_{x}^{2} + u_{y}^{2}} = \sqrt{{(10)}^{2} + {(10)}^{2}} \approx 14 {ms}^{- 1} .$

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