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Q.

A cylindrical uniform rod of mass 0.72 kg and radius 6 cm rests on two parallel rails, that are d=50 cm apart. The rod carries a current I=48A (In the direction shown) and rolls along the rails without slipping. If it starts from rest, uniform magnetic field of magnitude 0.25 T is directed perpendicular to the rod and the rail, then find the friction force (ln N) between rod and rails
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answer is 2.

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Detailed Solution

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f=F3idB3⇒  48×0.5×0.253=2.00

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