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A cylindrical vessel filled with water up to a height of 2m stands on a horizontal plane. The side wall of the vessel has plugged circular hole touching the bottom. The minimum diameter of the hole, so that the vessel begins to move on the floor if the plug is removed, will be....
(The coefficient of friction between the bottom of the vessel and the plane is 0.4, and total mass of water plus vessel is 100 kg)

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d = 0.112 m

d = 0.113 m

d = 1.13 m

d = 0.056m

answer is C.

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Detailed Solution

$\begin{array}{l} {ρAV}^{2} = μmg \\ V = \sqrt{2 gh} \\ ρπ \frac{d^{2}}{4} 2 gh = μmg \\ d^{2} = \frac{2 μm}{ρπh} d = \sqrt{\frac{2 μm}{ρπh}} \end{array}$

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