A cylindrical water container of radius $56 \mathrm{cm}$ and height of $180 \mathrm{cm}$ is to be made from metal. What is the area of metal required? Take $\pi =\frac{22}{7}$

Concept: The area of material required will be equal to the total surface area of the cylinder.

We know the total surface area of the cylinder $=2\pi rh+2\pi r^2$.

$\Rightarrow \left(2\times \frac{22}{7}\times 0.56\times 1.8\right)+2\times \frac{22}{7}\times {(0.56)}^2$

$\Rightarrow 8.3072 {\text{m}}^2$

Hence, the area of metal required is $8.3072 {\text{m}}^2$.