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Q.

A cylindrical wire of radius 0.5 mm and conductivity 5×107S/m is subjected to an electric field of 10 mV/m. The expected value of current in the wire will be x3πmA. The value of ‘x’ is

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answer is 5.

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Detailed Solution

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J=IA=σEI=AσE=πr25×107×10×10−3=π0.5×10−3250×104I=π×125×10−3A=125πmAx=(125)1/3=5

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