The motor is listed as running at 220 V. When operating at full speed, the initial current and power are both provided, therefore we must now take into account the emf and potential difference independently.

Using ohm’s law $V=Ir$

$220=20\times r$
$r=11\Omega$
Consequently, the resistance manifests as $11\Omega$, additionally, given that the starter's resistance is $6\Omega$. The result is that the circuit's overall resistance is $11\Omega$ the starter's reluctance, though, $(11-6)=5\Omega$
The motor's current consumption when operating at maximum speed must now be determined. $500 \mathrm{W}$ of power.
Using the formula, $P=i^{2}R$
$500=i^2\times 5$

$i=10 \mathrm{A}$

Hence, the correct answer is option B.