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A decimolar solution of potassium ferrocynide is 50% dissociated at 300K. Calculate the Osmotic pressure of the solution

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$7.48 \times 10^{5} N / m^{2}$

$6.67 \times 10^{5} N / m^{2}$

$1.32 \times 10^{5} N / m^{2}$

$3.2 \times 10^{5} N / m^{2}$

answer is A.

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Detailed Solution

$\begin{aligned} \underset{1 - x}{K_{4} [Fe (CN)_{6}]} \to \underset{4 x}{4 K^{+}} + \underset{x}{{[Fe (CN)_{6}]}^{4 -}} \end{aligned}$

$i = \frac{1 - x + 4 x + x}{1} = 1 + 4 \times 0.5 = 3$

$π = i C R T$

$= 3 \times (0.1 \times 10^{3}) \times 8.314 \times 300$

$= 7.48 \times 10^{5} N / m^{2}$

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