A detector is released from rest over a source of sound of frequency f0 = 103Hz. The frequency observed by the detector at time t is plotted in the graph. The speed of sound in air is: (g = 10m/s2)

From the given graph, it is clear that t=30sV0 = gt = 300 ms-1 ∴n1=V+V0Vn⇒2000=V+300V1000 ⇒V=300 ms-1

A detector is released from rest over a source of sound of frequency f0 = 103Hz. The frequency observed by the detector at time t is plotted in the graph. The speed of sound in air is: (g = 10m/s2)

From the given graph, it is clear that t=30sV0 = gt = 300 ms-1 ∴n1=V+V0Vn⇒2000=V+300V1000 ⇒V=300 ms-1

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A detector is released from rest over a source of sound of frequency f₀= 10³Hz. The frequency observed by the detector at time t is plotted in the graph. The speed of sound in air is: (g = 10m/s²)

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330 m/s

350 m/s

300 m/s

310 m/s

answer is C.

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Detailed Solution

From the given graph, it is clear that t=30s
V₀ = gt = 300 ms^-1

$∴ n^{1} = [\frac{V + V_{0}}{V}] n$
$\Rightarrow 2000 = [\frac{V + 300}{V}] 1000 \Rightarrow V = 300 {ms}^{- 1}$

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A detector is released from rest over a source of sound of frequency f0 = 103Hz. The frequency observed by the detector at time t is plotted in the graph. The speed of sound in air is: (g = 10m/s2)

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A detector is released from rest over a source of sound of frequency f₀= 10³Hz. The frequency observed by the detector at time t is plotted in the graph. The speed of sound in air is: (g = 10m/s²)