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Q.

A deuteron (the nucleus of an isotope of hydrogen) has a mass of 3.34×10-27kg and a charge of ve. The deuteron travels in a circular path with a radius of 6.96mm in a magnetic field with magnitude 2.50 T. Through what potential difference would the deuteron have to be accelerated to acquire this speed?

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a

V=r2B2q2m

b

V=r2B2qm

c

V=rB2q2m

d

V=r2Bq2m

answer is A.

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Detailed Solution

r=2qVmBq ∴V=r2B2q22qm=r2B2q2m

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