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Q.

A di negative ion  contains 8 protons and 9 neutrons. Number of electrons present in the ion is 

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a

8

b

11

c

6

d

10

answer is D.

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Detailed Solution

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Neutral atom contains 8 protons, 9 neutrons and 8 electrons. Anion carries more electrons than protons.For every unit negative charge electron increases by 1 unit. Total number electrons = 8 + 2 = 10

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