A diatomic gas contained in a vessel is subjected to a thermodynamic process such that its pressure changes with volume as shown in figure Change of internal energy during the process is $(γ = \frac{7}{5})$ :

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$7 .6 \times 10^{5} J$

4.5 x 10⁵ J

$5 .7 \times 10^{5} J$

$3 .2 \times 10^{5} J$

answer is A.

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Detailed Solution

$\begin{array}{l} ΔU = \frac{P_{2} V_{2} - P_{1} V_{1}}{γ - 1} \\ = \frac{4 \times 10^{5} \times 0 .5 - 2 \times 10^{5} \times 0 .1}{\frac{7}{5} - 1} \\ = 4 .5 \times 10^{5} J \end{array}$

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