A diatomic gas having CP=72R and CV=52R, is heated at constant pressure. The ratio dU:dQ:dW,

CP=72R,CV=52Rdu=nCVdt=n×52RdTdQ=nCPdT=n×72RdTdw=nRdTdU:dQ:dW=52:72:1=5:7:2

A diatomic gas having CP=72R and CV=52R, is heated at constant pressure. The ratio dU:dQ:dW,

CP=72R,CV=52Rdu=nCVdt=n×52RdTdQ=nCPdT=n×72RdTdw=nRdTdU:dQ:dW=52:72:1=5:7:2

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A diatomic gas having $C_{P} = \frac{7}{2} R$ and $C_{V} = \frac{5}{2} R,$ is heated at constant pressure. The ratio dU:dQ:dW,

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3:5:2

5:7:2

5:7:3

3:7:2

answer is B.

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Detailed Solution

$C_{P} = \frac{7}{2} R, C_{V} = \frac{5}{2} R$

$d u = n C_{V} d t = n \times \frac{5}{2} R d T$

$d Q = n C_{P} d T = n \times \frac{7}{2} R d T$

$d w = n R d T$

$d U : d Q : d W = \frac{5}{2} : \frac{7}{2} : 1$

$= 5 : 7 : 2$

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A diatomic gas having CP=72R and CV=52R, is heated at constant pressure. The ratio dU:dQ:dW,

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A diatomic gas having $C_{P} = \frac{7}{2} R$ and $C_{V} = \frac{5}{2} R,$ is heated at constant pressure. The ratio dU:dQ:dW,