A diatomic gas which has initial volume of 10 Liter is isothermally compressed to 115th of its original volume where initial Pressure is 105 pascal. If temperature is 270 C then find the work done by gas

W = nRTlnV2V1=P0V0lnV2V1=105×10×10-3ln115 = -2.70×103 J

A diatomic gas which has initial volume of 10 Liter is isothermally compressed to 115th of its original volume where initial Pressure is 105 pascal. If temperature is 270 C then find the work done by gas

W = nRTlnV2V1=P0V0lnV2V1=105×10×10-3ln115 = -2.70×103 J

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A diatomic gas which has initial volume of $10 L i t e r$ is isothermally compressed to $\frac{1}{15^{t h}}$ of its original volume where initial Pressure is $10^{5} p a s c a l$ . If temperature is $27^{0} C$ then find the work done by gas

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$2.70 \times 10^{3} J$

$- 7.70 \times 10^{3} J$

$- 2.70 \times 10^{3} J$

$- 2 \times 10^{3} J$

answer is A.

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Detailed Solution

$W = n R T \ln (\frac{V_{2}}{V_{1}}) = P_{0} V_{0} \ln (\frac{V_{2}}{V_{1}}) = 10^{5} \times 10 \times 10^{- 3} \ln (\frac{1}{15}) = - 2.70 \times 10^{3} J$

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A diatomic gas which has initial volume of 10 Liter is isothermally compressed to 115th of its original volume where initial Pressure is 105 pascal. If temperature is 270 C then find the work done by gas

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A diatomic gas which has initial volume of $10 L i t e r$ is isothermally compressed to $\frac{1}{15^{t h}}$ of its original volume where initial Pressure is $10^{5} p a s c a l$ . If temperature is $27^{0} C$ then find the work done by gas