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Q.

A diatomic ideal gas initially at 273K is given 100cal heat due to which system performed 209J work. Molar heat capacity (C_m) of gas for the process is $(y × R)$ , then the value of “y” is (R= gas constant in joule,k^-1,mol^-1)

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answer is 5.

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Detailed Solution

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$Δ E = q + w = 100 - \frac{209}{4.18} = 100 - 50 = 50 c a l$

$Δ E = n C_{v, m} Δ T, q = n C_{m} Δ T$

$\frac{q}{Δ E} = \frac{C_{m}}{C_{v, m}}; C_{m} = 2 C_{v, m} = 5 R$

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