A die is thrown, calculate the probability of getting a number greater than 3.

$P\left(E\right)=\frac{\text{ no. of outcomes favourable to event }E}{\text{ Total no. of}\text{ outcomes}}$

Writing possible sample space

Given: A die is rolled once

 Total number of outcomes $=6$

Also, we have to find the probability of getting number greater than 3,

Outcomes greater than $3=\{4,5,6\}$

Number of favourable outcomes $=3$

Therefore , the Probability of getting a number greater than 3,

$P\left(E\right)=\frac{\text{ no. of outcomes favourable to event }E}{\text{ Total no. of}\text{ outcomes}}$

$\Rightarrow P=\frac{3}{6}$

$\Rightarrow P=\frac{1}{2}$