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A die is tossed once. Find the probability of getting a prime number.

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12

13

14

None of the above

answer is A.

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Detailed Solution

Given that a die is tossed once.
We need to find the probability of getting a prime number.
Probability of an event E is defined as:

P (E) = \frac{Number of favorable outcomes}{Total number of possible outcomes}

There are 6 possible outcomes when a die is thrown: 1, 2, 3, 4, 5, 6
Therefore, the total number of possible outcomes is 6.
Let

E

be the event that a prime number is obtained.
We know, 2, 3 and 5 are the prime numbers, therefore there are 3 favorable outcomes.
Probability of getting a prime number is,

P E = 36 ⇒ P E = 12

Hence, the probability of getting a prime number is

12

.
Therefore, option 1 is correct.

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