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A die is tossed once. Find the probability of getting an even number or a multiple of 3.

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16

23

13

34

answer is B.

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Detailed Solution

Give that a die is tossed.
We need to find the probability of getting an even number or a multiple of 3.
Probability of an event E is defined as:

P (E) = \frac{Number of favorable outcomes}{Total number of possible outcomes}

When a die is thrown, we have 6 total possible outcomes i.e.,

1, 2, 3, 4, 5, 6

Numbers that are even number or a multiple of 3 are:
2,3,4,6
Hence, the number of favorable outcomes is 4.
Let

E

be the event that the number is an even number or a multiple of 3.
Now, the probability of getting an even number or a multiple of 3 is:

P (E) = 46 ⇒ P (E) = 23

The probability of getting an even number or a multiple of 3 is

23

.
Therefore, option 2 is correct.

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