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A die is tossed thrice if event of getting an even number is a success then the probability of getting at least 2 successes is

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$\frac{7}{8}$

$\frac{1}{4}$

$\frac{2}{3}$

$\frac{1}{2}$

answer is D.

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Detailed Solution

$P (X \geq 2) = P (X = 2) + P (X = 3)$

$=^{3} C_{2} {(\frac{1}{2})}^{3 - 2} {(\frac{1}{2})}^{2} +^{3} C_{3} {(\frac{1}{2})}^{3 - 3} {(\frac{1}{2})}^{3} = \frac{3}{8} + \frac{1}{8} = \frac{1}{2}$

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