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Q.

A dielectric is placed in between the two parallel plates of a capacitor as shown in figure, the dielectric constant of the dielectric being K. If the initial capacity is C, then the new capacity will be

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a

$(K - 1) C$

b

$K C$

c

$C (K + 1) / 2$

d

$(K + 1) C$

answer is C.

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Detailed Solution

$\begin{array}{l} C_{1} = \frac{\in_{0} (A / 2)}{d} = \frac{C_{0}}{2} \\ C_{2} = \frac{K \in_{0} (\frac{A}{2})}{d} = \frac{K C o}{2} \end{array}$

$∴ C_{e f f} = (\frac{K + 1}{2}) C_{0}$

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