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Q.

A diode  having potential  difference 0.5V across its junction which does not depend  on  current. It is connected  in series with resistance  of  40Ω  across source.  If 0.4A passes   through the resistance,   what is  the voltage of source?

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a

0.02 V

b

1.65 V

c

3.3 V

d

16.5 V

answer is A.

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Detailed Solution

VS=VD+IR ⇒VS=0.5+0.4×40 =16.5 V

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