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Q.

A dip circle is so set that the dip needle moves freely in the magnetic meridian. In this position the angle of dip is 39°. Now the dip circle is rotated so that the plane in which the needle moves makes an angle of 30° with the magnetic meridian. In this position, the needle will dip by an angle :

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a

exactly 39°

b

more than 39°

c

less than 39°

d

30°

answer is C.

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Detailed Solution

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$\frac{\tan δ}{\tan δ'} = \cos α$
$\tan δ' = \frac{\tan δ}{\cos α}$
since $\cos α < 1$
$∴ \tan δ' > \tan δ$
$δ' > δ$

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A dip circle is so set that the dip needle moves freely in the magnetic meridian. In this position the angle of dip is 39°. Now the dip circle is rotated so that the plane in which the needle moves makes an angle of 30° with the magnetic meridian. In this position, the needle will dip by an angle :