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A dip needle is taken to magnetic north pole and it is allowed to oscillate. The time period of oscillation is found to be T. Now the same dip needle is taken to magnetic equator and allowed to oscillate. This time the time period of oscillation is found to be T'. Then

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T' = T

T' may be greater than T.

T' > T

T' < T

answer is B.

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Detailed Solution

Time period $= 2 π \sqrt{\frac{I}{MB}}$

When $I$ = Moment of inertia , B = Earth's resultant magnetic field , M = Magnetic dipole moment of the needle.

Now, resultant magnetic field at magnetic north pole is more intense then that at the magnetic equator.

Hence, T' > T.

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